Aug 5, 2007 · I thought that horizontal asymptotes were asymptotes and now I'm hearing that they can be crossed... Is this true? If so, why and how? Okay, wait a...

Jun 8, 2010 · Hi guys, I was trying to sketch a polar curve but my curve was different from the curve on maple(I plotted the same curve on maple). Homework Statement Here is the whole …

Oct 24, 2011 · Let's say I'm trying to find the oblique asymptote of the function: f(x)= -3x2 + 2 x-1 Forgive my poor formatting. So because the denominator isn't linear, we do polynomial long …

Oct 1, 2007 · The thing I have noticed is that parabola's angle from the x-axis keeps increasing...meaning the object is decreasing from that direction...if that is the case, then how …

Aug 9, 2009 · Infliction point exist where concavity changes. Say y=a is a vertical asymptote. If f(x) approaches infinity from the left and negative infinity from the right. Since on the left is …

Feb 22, 2009 · I seem to be having a lot of difficulty finding whether for a horizontal asymptote, whether the curve approaches the asymptote from above or below. For example, for the …

Jul 11, 2005 · I'm having trouble figuring the oblique asymptote for this problem... I haven't ever done one of these before so I really don't know where to start...

Apr 14, 2017 · Asymptote of a curve in polar coordinates Faiq Apr 14, 2017 Asymptote Coordinates Curve Polar Polar coordinates Proofs

Sep 27, 2009 · The slant asymptote for x → +∞ is y = x + 1, confirmed through both long division and limit analysis, while for x → -∞, the asymptote is y = -x - 1. The discussion emphasizes the …

Jan 2, 2006 · Find the vertical asymptotes of the graph of F(x) = (3 - x) / (x^2 - 16) ok if i factor the denominator.. i find the vertical asymptotes to be x = 4, x = -4. The 2nd part of the problem …